Main
RANGE OF PRODUCT
Modicon Quantum automation platform
PRODUCT OR COMPONENT TYPE
Hot standby module
SOFTWARE DESIGNATION
Concept >= V2.0
ProWORX 32 NxT V2.0
Complementary
PRODUCT COMPATIBILITY
All 140CPU43412A/534 with IEC language
All legacy 140CPU with LL984 language
INPUT/OUTPUT TYPE
Quantum
800 Series
Sy/Max (remote I/O only)
TRANSMISSION RATE
10 Mbit/s
TRANSMISSION SUPPORT MEDIUM
Fiber optic 9.84 ft (3 m)
SWITCHING TIME
13…48 ms
ELECTRICAL CONNECTION
1 connector RJ45 for fiber optic receiver
1 connector RJ45 for fiber optic transmitter
LOCAL SIGNALLING
1 LED amber module in standby
1 LED green communication with I/O module
1 LED green control process
1 LED green ready module
1 LED red communication error
BUS CURRENT REQUIREMENT
700 mA
MODULE FORMAT
Standard
PRODUCT WEIGHT
2.34 lb(US) (1.06 kg)
Environment
RFI IMMUNITY
27…1000 MHz 9.14 V/yd (10 V/m) conforming to IEC 60801-3
RESISTANCE TO ELECTROSTATIC DISCHARGE
4 kV contact
8 kV air
AMBIENT AIR TEMPERATURE FOR OPERATION
32…140 °F (0…60 °C)
AMBIENT AIR TEMPERATURE FOR STORAGE
-40…185 °F (-40…85 °C)
RELATIVE HUMIDITY
95 % without condensation
OPERATING ALTITUDE
<= 16404.2 ft (5000 m)
Ordering and shipping details
CATEGORY
18150 – QUANTUM CONTROLLERS,HSBY,COMM.
DISCOUNT SCHEDULE
PC21
GTIN
00785901104339
NBR. OF UNITS IN PKG.
1
PACKAGE WEIGHT(LBS)
2.21
RETURNABILITY
N
COUNTRY OF ORIGIN
FR
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Our Repair Services
MRO Electric repairs CNCs, PLCs, Servo/Spindle Drives, Motors, Amplifiers, VFDs, HMIs, and more, most of which can be repaired in only 3-5 days.
Repair Benefits
MRO can restore your failed 140CHS11000 to remanufactured condition and save you up to 75% compared to buying new. We offer standard repair pricing to ensure you the best value for your repair.
Our certified technicians use rigorous testing procedures to ensure your parts are restored to fully functioning condition. Our team proudly stands behind all repairs by providing a minimum 12-month warranty.
Our technicians have vast experience with most manufacturers and models. In addition to this 140CHS11000 we also repair drives, motors, PLCs and more, so if you don’t see the model you need, please contact us.
Core Exchange
If you are interested in getting credit for your faulty 140CHS11000, just let us know and we can issue you an RMA to send it in as an exchange. Our exchange program provides you with savings and keeps us stocked for the next time you need anything.
1. Polynomial rings
Let R be a ring and x1, . . . , xd indeterminates over R. For m = (m1, . . . , md) ∈ Nd
, let
x
m = x
m1
1
· · · x
md
d
. Then the polynomial ring S = R[x1, . . . , xd] is a graded ring, where
Sn = {
X
m∈Nd
rmx
m | rm ∈ R and m1 + · · · + md = n}.
This is called the standard grading on the polynomial ring R[x1, . . . , xd]. Notice that
S0 = R and deg xi = 1 for all i. There are other useful gradings which can be put on S.
Let (α1, . . . , αd) ∈ Z
d Then the subgroups {Sn} where
Sn = {
X
m∈Nd
rmx
m | rm ∈ R and α1m1 + · · · + αdmd = n}
defines a grading on S. Here, R ⊆ S0 and deg xi = αi
for all i.
As a particular example, let S = k[x, y, z] (where k is a field) and f = x
3 + yz. Under
the standard grading of S, the homogeneous components of f are x
3 and yz. However,
if we give S the grading induced by setting deg x = 3, deg y = 4, deg z = 5, then f is
homogeneous of degree 9.
2. Graded subrings
Definition 1.2. Let S = ⊕Sn be a graded ring. A subring R of S is called a graded
subring of S if R =
P
n
(Sn ∩ R). Equivalently, R is graded if for every element f ∈ R all
the homogeneous components of f (as an element of S) are in R.
Exercise 1.3. Let S = ⊕Sn be a graded ring and f1, . . . , fd homogeneous elements of S
of degrees α1, . . . , αd, respectively. Prove that R = S0[f1, . . . , fd] is a graded subring of S,
where
Rn = {
X
m∈Nd
rmf
m1
1
· · · f
md
d
| rm ∈ S0 and α1m1 + · · · + αdmd = n}.
Then R(I) is a graded subring of R[t] where R(I)n = {atn | a ∈ In}. The advantatage to
this approach is that the exponent of the variable t identifies the degrees of the homogeneous
components of a particular element of R(I).
Exercise 1.4. Let R be a ring, I = (a1, . . . , ak)R a finitely generated ideal, and I = {I
n}.
Prove that R(I) = R[a1t, . . . , akt]. Generalize this statement to arbitrary ideals.
In the case I = {I
n} where I is an ideal of R, we call R(I) the Rees algebra of I and
denote it by R[It]. By the above exercise, R[It] is literally the smallest subring of R[t]
containing R and It. As a particular example, let R = k[x, y] and I = (x
Given any graded R-module M, we can form a new graded R-module by twisting the grading on M as follows: if n is any integer, define M(n) (read “M twisted by n”) to be equal to M as an R-module, but with it’s grading defined by M(n)k = Mn+k. (For example, if M = R(−3) then 1 ∈ M3.) Exercise 1.5. Show that M(n) is a graded R-module. Thus, if n1, . . .nk are any integers then R(n1) ⊕ · · · ⊕ R(nk) is a graded R-module. Such modules are called free. We can also obtain graded modules by localizing at a multiplicatively closed set of homogeneous elements, as illustrated in the following exercise: Exercise 1.6. Let R be a graded ring and S a multiplicatively closed set of homogeneous elements of R. Prove that RS is a graded ring